To calculate the oxidant dosage required treating waste water, we need to know how much reactive oxygen [O] is available from the oxidant.

Om die vlak van doseering van oksidant te bepaal vir die behandeling van afval water benodig ons die hoeveelheid reaktiewe suurstof (O) wat beskikbaar is van die oksidant

Chlorine Cl2+ H2O --> [O] + 2Cl-+ 2H+ 

Hypochlorite HOCl --> [O] + C+ H 

Chlorine Dioxide 2ClO2+ H2O --> 5[O] + 2Cl-+ 2H

Ozone O3---> [O] + O2 Peroxide H2O2---> [O] + H2O

Permanganate MnO4+H2O ---> 3[O] + MnO2+ 2OH- Ferrate 2FeO4-2+ H2O ---> 3[O] + Fe2O3+ 4OH-
 
Thus, chlorine dioxide is a much more efficient oxidant than peroxide or ozone since it generates five (5) reactive oxygen’s compared to peroxide and ozone, which generates one (1).The calculation used to estimate dosage in a waste water system is:

Dus is chloor dioksied ‘n baie meer effektiewe oksidant as peroksied of osoon aangesien dit vyf (5) reaktiewe suurstowwe genereer teenoor die (1) van peroksied en osoon. Die berekening wat ons gebruik om die doseering te bepaal in ‘n afval water sisteem is:
 
Oxidant Dosage (ppm) = ((Mw of Oxidant)/16n) x COD

Mw=molekulere gewig van oksidant n = aantal reaktiewe suurstowwe gegenereer

COD= “Chemical Oxygen Demand” van die water
 
Dus, vir ’n sisteem van 500ppm COD sal dit ‘n berekende 419ppm Chloor dioksied neem om die COD te verwerk na ‘n nie-oksideerbare spesie, CO2 en H20

Where Mw is the molecular weight of the oxidant, n is the number of reactive oxygen’s generated and COD is the Chemical Oxygen Demand of the water. Thus, for a system with 500 ppm COD, it will take a calculated 419 ppm chlorine dioxide to convert the COD to nonoxidisable species, CO2and H2O.
 
Calculation:
 
Dosage = ((67/16x5)) x 500    Dosage = (0.83)(500